SOLUTION: Find value(s) of k such that y=kx-3 is tangent to the parabola y=2x^2+ 10

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Question 1181587: Find value(s) of k such that y=kx-3 is tangent to the parabola y=2x^2+ 10
Answer by Edwin McCravy(20055)   (Show Source): You can put this solution on YOUR website!
Find value(s) of k such that y=kx-3 is tangent to the parabola y=2x^2+ 10
If you haven't had calculus, then we do it this way:

A line is tangent to a parabola if and only if the assumption of their
equations holding true leads to a single solution with multiplicity 2.

We substitute (kx-3) for y in 






This will have a single solution with multiplicity 2 if its discriminant
equals 0.








Those are the two and the only such values of k.

Edwin


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