SOLUTION: a trader buy some eggs at #15 she find that five of them are broken she sells the rest of #20 each and make a profit of #340 how many eggs did she buy

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Question 1174828: a trader buy some eggs at #15 she find that five of them are broken she sells the rest of #20 each and make a profit of #340 how many eggs did she buy
Answer by ikleyn(52776)   (Show Source): You can put this solution on YOUR website!
.
A trader buys some eggs at #15 she find that five of them are broke.
She sells the rest of #20 each and make a profit of #340 how many eggs did she buy ?
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Let x be the number of eggs she bought.


The buying cost was  15x  monetary units.


She sold (x-5) eggs for the selling cost of  20*(x-5) monetary units.


Her profit was  340 monetary units.



It gives you this MONEY equation


    Selling cost - Buying cost = profit,   

or

    20*(x-5)     -     15x     = 340.



Simplify and solve


    20x - 100 - 15x = 340

    20x - 15x       = 340 + 100

       5x           = 440

        x           = 440/5 = 88.


ANSWER.  She bought 88 eggs.


CHECK.   Bying cost = 15*88.  Selling cost = 20*83.  The profit = Selling - Bying = 20*83 - 15*88 = 340.  ! Correct !

Solved.



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