SOLUTION: Fruit & Veg shop sells water in 5-litre bottles. 2.1 On Wednesday Fruit & Veg shop received $2 530 from selling 5-litre bottles of water at $11.50 per bottle. How many litres of

Question 1168301: Fruit & Veg shop sells water in 5-litre bottles.
2.1 On Wednesday Fruit & Veg shop received $2 530 from selling 5-litre bottles of water at $11.50
per bottle. How many litres of water were sold on that day?
2.2 On Thursday, the shop received x $ by selling 5-litre bottles of water at 50 . 11 $ each. In terms
of ,x how many litres of water were sold on that day?
2.3 On Friday the shop received $(x  20) by selling 5-litre bottles of water at $9 each. In terms
of x, how many litres of water were sold on that day?
2.4 If the number of bottles sold on Thursday equal to the number of bottles sold on Friday, how many
bottles of water were sold in each of these two days?
Answer by CPhill(1959) (Show Source): You can put this solution on YOUR website!
Let's break down each part of the problem:
**2.1 On Wednesday:**
* **Price per bottle:** $11.50
* **Total revenue:** $2530
To find the number of bottles sold, we divide the total revenue by the price per bottle:
Number of bottles = Total revenue / Price per bottle
Number of bottles = $2530 / $11.50 = 220 bottles
Since each bottle contains 5 litres of water, the total litres of water sold on Wednesday is:
Total litres = Number of bottles × Litres per bottle
Total litres = 220 bottles × 5 litres/bottle = 1100 litres
**Answer to 2.1: 1100 litres of water were sold on Wednesday.**
**2.2 On Thursday:**
* **Price per bottle:** $11
* **Total revenue:** $x
To find the number of bottles sold, we divide the total revenue by the price per bottle:
Number of bottles = Total revenue / Price per bottle
Number of bottles = $x / $11 = \frac{x}{11}$ bottles
Since each bottle contains 5 litres of water, the total litres of water sold on Thursday is:
Total litres = Number of bottles × Litres per bottle
Total litres = $\frac{x}{11}$ bottles × 5 litres/bottle = $\frac{5x}{11}$ litres
**Answer to 2.2: $\frac{5x}{11}$ litres of water were sold on Thursday.**
**2.3 On Friday:**
* **Price per bottle:** $9
* **Total revenue:** $(x - 20)$
To find the number of bottles sold, we divide the total revenue by the price per bottle:
Number of bottles = Total revenue / Price per bottle
Number of bottles = $\frac{(x - 20)}{9}$ bottles
Since each bottle contains 5 litres of water, the total litres of water sold on Friday is:
Total litres = Number of bottles × Litres per bottle
Total litres = $\frac{(x - 20)}{9}$ bottles × 5 litres/bottle = $\frac{5(x - 20)}{9}$ litres
**Answer to 2.3: $\frac{5(x - 20)}{9}$ litres of water were sold on Friday.**
**2.4 If the number of bottles sold on Thursday equals the number of bottles sold on Friday:**
From our answers to 2.2 and 2.3, the number of bottles sold on Thursday is $\frac{x}{11}$ and the number of bottles sold on Friday is $\frac{x - 20}{9}$. We are given that these are equal:
$\frac{x}{11} = \frac{x - 20}{9}$
To solve for x, we can cross-multiply:
$9x = 11(x - 20)$
$9x = 11x - 220$
Now, isolate x:
$220 = 11x - 9x$
$220 = 2x$
$x = \frac{220}{2}$
$x = 110$
Now that we have the value of x, we can find the number of bottles sold on Thursday and Friday:
Number of bottles on Thursday = $\frac{x}{11} = \frac{110}{11} = 10$ bottles
Number of bottles on Friday = $\frac{x - 20}{9} = \frac{110 - 20}{9} = \frac{90}{9} = 10$ bottles
**Answer to 2.4: 10 bottles of water were sold on each of these two days.**
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