# SOLUTION: x+2y=7 x+3 =8 3x+5y=17 4x-3y=2 solve the system using the any algebraic method

Algebra ->  Algebra  -> College  -> Linear Algebra -> SOLUTION: x+2y=7 x+3 =8 3x+5y=17 4x-3y=2 solve the system using the any algebraic method       Log On

 Algebra: Linear Algebra (NOT Linear Equations) Solvers Lessons Answers archive Quiz In Depth

 Question 112652: x+2y=7 x+3 =8 3x+5y=17 4x-3y=2 solve the system using the any algebraic method Answer by chitra(359)   (Show Source): You can put this solution on YOUR website!the first set of equation is: x + 2y = 7 and 3x + 5y = 17 Multiply EQN(1) by 3 and subtract it from the second equation. We get: 3x + 6y = 21 3x + 5y = 17 =========== y = 4 Substituting in one of the equations we can find the value of x x + 2(4)= 7 ==> x = 7 - 8 ==> x = -1 The second set of equations are: x + 3y = 8 and 4x - 3y = 2 Adding the equations we get: x + 3y = 8 4x - 3y = 2 =========== 5x = 10 ==> x = x = 2 By back substitution we can find the value of y. 2 + 3y = 8 3y = 8 - 2 3y = 6 y = y = 2 thus the solution NOTE: If these are not the set of equations then mail me back with the correct set of equations wil send you the answers as soon as possible. Regards