SOLUTION: x+2y=7 x+3 =8 3x+5y=17 4x-3y=2 solve the system using the any algebraic method

Question 112652: x+2y=7 x+3 =8
3x+5y=17 4x-3y=2
solve the system using the any algebraic method

Answer by chitra(359) (Show Source): You can put this solution on YOUR website!
the first set of equation is:

x + 2y = 7 and 3x + 5y = 17

Multiply EQN(1) by 3 and subtract it from the second equation. We get:

3x + 6y = 21
3x + 5y = 17
===========
y = 4

Substituting in one of the equations we can find the value of x

x + 2(4)= 7

==> x = 7 - 8

==> x = -1

The second set of equations are:

x + 3y = 8 and 4x - 3y = 2

Adding the equations we get:

x + 3y = 8
4x - 3y = 2
===========
5x = 10

==> x =

x = 2

By back substitution we can find the value of y.

2 + 3y = 8

3y = 8 - 2

3y = 6

y =

y = 2

thus the solution

NOTE: If these are not the set of equations then mail me back with the correct set of equations wil send you the answers as soon as possible.

Regards

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