SOLUTION: Hi The question is A man bought a lot of lemons for �5; for one third he paid 4p a piece; and for the rest 3p a piece. How many lemons did he buy? Thank you

Question 1112870: Hi
The question is
A man bought a lot of lemons for �5; for one third he paid 4p a piece; and for the rest 3p a piece. How many lemons did he buy?
Thank you
Answer by greenestamps(13203) (Show Source): You can put this solution on YOUR website!

For 1/3 of the lemons he paid 4p each, for the other 2/3 he paid 3p each. That means he bought twice as many at 3p each as he bought at 4p each.

So consider "packages" of 1 lemon at 4p and 2 lemons at 3p each. Each of those packages costs 10p, so for �5 he can buy 50 of those packages.

Since there are 3 lemons in each package, the number of lemons he bought was 50*3 = 150.

Algebraically....

Let x be the total number of lemons.
Then he bought (1/3)x lemons at 4p each and (2/3)x lemons at 3p each; and the total cost was �5 = 500p. So

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