SOLUTION: 4(r-5)+1>5(r+2)-28

Algebra.Com
Question 1109948: 4(r-5)+1>5(r+2)-28
Answer by Boreal(15235)   (Show Source): You can put this solution on YOUR website!
4(r-5)+1>5(r+2)-28
4r-20+1>5r+10-28
4r-19>5r-18
-r > 1
r < -1, note flipping of inequality ANSWER
Check
-2 should work
4(-7)+1 >-28, which is true
0 should not work
-20+1 > 20-28
-19 > -8 which is not true

RELATED QUESTIONS

5(r-8)+4>6(r+2)-28 solve (answered by MRperkins)
r+4/r=... (answered by edjones)
Simplify 4(r^5)^-1/... (answered by Boreal)
Let r_1, r_2, r_3, r_4, and r_5 be the complex roots of x^5 - 4x^2 + 7x - 1 = 0. Compute (answered by CPhill,ikleyn)
Please help me solve for R for this equation: {{{(3/(5+R)) + (R/(R+2))=(R+4)/(R+5)... (answered by rmromero)
6/r - 5/r-2... (answered by rapaljer)
2/r + 6/r-5 (answered by erica65404)
(768/r^5)r^2 (answered by ikleyn)
6(r - 1) + 5(r +... (answered by rfer)