SOLUTION: Let A= [1 2 3 5;2 4 8 12;3 6 7 13] I have already reduced the matrix to [1 2 3 5;0 0 1 1;0 0 0 0] I need help solving the next step which is to find the general solution in t

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Question 1061938: Let A= [1 2 3 5;2 4 8 12;3 6 7 13] I have already reduced
the matrix to [1 2 3 5;0 0 1 1;0 0 0 0] I need help
solving the next step which is to find the general
solution in the form x=xh + p of Ax= (0, 6, -6)T


Answer by Edwin McCravy(20056)   (Show Source): You can put this solution on YOUR website!
Let A= [1 2 3 5;2 4 8 12;3 6 7 13] I have already reduced
the matrix to [1 2 3 5;0 0 1 1;0 0 0 0] I need help
solving the next step which is to find the general
solution in the form x=xh + p of Ax= (0, 6, -6)T
 
Matrix A is an abbreviation for this system of equations:



You have reduced the matrix down to this, call it B:



That reduced matrix is an abbreviation for this system of equations:



Eliminating all the 0 terms and the 1 coefficients:



Substitute 1 for z in the first equation:








So the general solution is

x = 2-2y
y = y
z = 1

or

(x, y, z) = (2-2y, y, 1)

That's the way most books like the general solution in.

I've never seen 

"the form x=xh + p of Ax= (0, 6, -6)T"
though I've taught college mathematics for many years.  I'm sure
it's equivalent to that, though. Some books will put a k for the y,
like this:

(x, y, z) = (2-2k, k, 1)

Edwin

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