SOLUTION: A ball is thrown directly upward from a height of 7 ft with an initial velocity of 20 ft/sec. The function s(t)=−16t^2+20t+7 gives the height of the ball

Question 1044875: A ball is thrown directly upward from a height of 7 ft with an initial velocity of 20 ft/sec. The function s(t)=−16t^2+20t+7 gives the height of the ball, in feet, t seconds after it has been thrown. Determine the time at which the ball reaches its maximum height and find the maximum height
Answer by ikleyn(52767)   (Show Source): You can put this solution on YOUR website!
.
A ball is thrown directly upward from a height of 7 ft with an initial velocity of 20 ft/sec.
The function s(t)=−16t^2+20t+7 gives the height of the ball, in feet, t seconds after it has been thrown.
Determine the time at which the ball reaches its maximum height and find the maximum height
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Similar problems were solved in lessons
    - Problem on a projectile moving vertically up and down
    - Problem on an arrow shot vertically upward
    - Problem on a ball thrown vertically up from the top of a tower
    - Problem on a toy rocket launched vertically up from a tall platform
in this site.

Chose the most appropriate to you. Consider it as a sample.
Read it attentively. Then solve your problem by substituting your data.

RELATED QUESTIONS
A ball is thrown directly upward from a height of 4 ft with an initial velocity of 24... (answered by ikleyn)

SOLUTION: A ball is thrown directly upward from a height of 7 ft with an initial velocity of 20 &#8203;ft/sec. The function &#8203;s(t)=&#8722;16t^2+20t+7 gives the height of the&#8203; ball