SOLUTION: find the basic for the subspace of IR^4 spanned by s: s={(2,9,-2,53),(-3,2,3,-2),(8,-3,-8,17),(0,-3,0,15)}.

SOLUTION: find the basic for the subspace of IR^4 spanned by s: s={(2,9,-2,53),(-3,2,3,-2),(8,-3,-8,17),(0,-3,0,15)}.

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Question 1044796: find the basic for the subspace of IR^4 spanned by s:
s={(2,9,-2,53),(-3,2,3,-2),(8,-3,-8,17),(0,-3,0,15)}.
Answer by robertb(5830) (Show Source): You can put this solution on YOUR website!
Is the fourth vector really (0,-3,0,15), or (0,-3,0,-15)?
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