SOLUTION: Write the equation of a line that passes through (0,6) and is perpendicular to x-3y=5

Question 1021683: Write the equation of a line that passes through (0,6) and is perpendicular to x-3y=5
Answer by macston(5194) (Show Source): You can put this solution on YOUR website!
Original equation:
x-3y=5
x-5=3y
(1/3)x-(5/3)=y
.
y=(1/3)x-(5/3) (RED line on graph)
.
The slope of the original line is 1/3,
so the slope of the perpendicular line would be -3.
.
Use x=0 and y=6 to find b.
y=mx+b
y=-3x+b
6=-3(0)+b
6=b
.
ANSWER: The equation is y=-3x+6 (GREEN line on graph)
.
GRAPH:

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