Hi 

Note:  the standard slope-intercept form for an equation of a line is 

  where m is the slope and b the y-intercept.  

It is as simple as solving the first of the two for y and comparing their slopes

-14x = -632 - 26y   0r 

 y = (7/13)x - 316/13  Lines are parallel 



5x + 4y = -60 0r 

 y = (-4/5)x - (3/5) Lines are perpendicular  negative reciprocals



-2y = -380 + 14x  0r  

 y = -7x + 190 Lines are parallel 

 

Answer by Boreal(15235)   (Show Source): You can put this solution on YOUR website!
 Look at the slopes after you have the equation in the form y=mx+b

The first is 26y=14x-632; y=(7/13)x-632/13

The second has slope 7/13.  These lines are parallel, and the intercepts are different.

-----------------------------------

-2y=-380+14x

y=-7x+190.  Slope is 7.  That is all that matters.

The other slope is (7/13).  These are not equal and they are neither parallel nor perpendicular.

--------

4y=-5x-60

y=(-5/4)x-60

The other is -4/5.  Their product is 1, not -1, so these are neither parallel nor perpendicular.

--------------

c. 6y=-x+196, y=-(1/6)x+(196/6)

the other has a slope of -4823/460, which is about 10.5, so they are neither.

--------------

The first has slope of -7 and is y=-7x+190

The second has slope of -7 and is y=-7x+190. They are the same line.

-----------------

 

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