# SOLUTION: A copy machine can copy a report in 30 mins. When a second copy machine is used at the same time, the copying can be sone in 18 min. How long would it take the second copu machine

Algebra ->  College -> SOLUTION: A copy machine can copy a report in 30 mins. When a second copy machine is used at the same time, the copying can be sone in 18 min. How long would it take the second copu machine       Log On

 Question 121891This question is from textbook : A copy machine can copy a report in 30 mins. When a second copy machine is used at the same time, the copying can be sone in 18 min. How long would it take the second copu machine to do the copying alone? i have: x=30 x+y=18 that would be -12..not right? This question is from textbook Answer by ankor@dixie-net.com(16554)   (Show Source): You can put this solution on YOUR website!A copy machine can copy a report in 30 mins. When a second copy machine is used at the same time, the copying can be done in 18 min. How long would it take the second copy machine to do the copying alone? : Nice try, but let's do it this way. : Let x = time required when using both machines. Let the completed job = 1 : we know that copy machine 1 will do x/30 of the job and copy machine 2 will do x/18 of the job : Together: Machine 1's fraction + Machine 2's fraction = the completed job (1) + = 1 : Get rid of those annoying denominators, multiply equation by 30*18 = 540 540* + 540* = 540(1) : Cancel out the denominators and you have: : 18x + 30x = 540 : 48x = 540 x = x = 11.25 minutes or we could say 11 min 15 secs : : Check our solution like this: 11.25/30 + 11.25/18 = .375 + .625 = 1 : Did this make sense to you? Enlighten you a little bit?