SOLUTION: how do you solve for a: 2x^2+y+3ab=5

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Question 549319: how do you solve for a: 2x^2+y+3ab=5
Answer by TutorDelphia(193) About Me  (Show Source):
You can put this solution on YOUR website!
"Solving for a" means getting a alone on the left.
Lets start by moving+2x%5E2+and y to the right side
3ab=-2x%5E2-y%2B5
Then we need to get rid of 3b by doing division.
a=%28-2x%5E2-y%2B5%29%2F3b